#Homo and lumo of ammonia plus

It will be as an oneness 1 because of the static strain there will be no son. The product formed will be, will be this here. The next is next compound is gromocyclopentome. That'S why snon mechanism is followed here now. N, 1 or or s m, the next compound is bromocycloexand, the product will be simply iodocyclohexen and this will go through s and 1 pand y s, n 1, due to the large size of stit, is difficult for nucleophilic or as into mechanism. So it only goes through nucleophilic substitution reaction. Here there will be no reaction because, as benzene is a very stabilized structure, so there is no side for s n, 1 or s n to attack, and it is a aromatic ring aromatic ring. the shift in energies and that in the D3h structure the HOMO and LUMO cannot mix because they are of different symmetry. This will form the product of thisnext compound given to us is bromobengineand. Formation of carbocatithis will be 1 car boatin and another 1 will be like this, and the boats will form products, sin 1 and a sin 1. There will be as none attack not asen, and here also there will be and 1 there will be. Also, there will be, there will be, as in 1, atom in case of tertiary butyl chloride. This is also as an 2 mechanism, and then i minus will attack the product will be thisnext. The HOMOLUMO gap decreases with increas- ing cluster size for most stable cyclic structures, indicating enhancement in their chemical softness and hence the. Here there will be the formation of carbocationbut. The product of the compound is tertiary, butyl chloride. NO molecules can narrow the HOMO-LUMO gaps, which is because both of molecule adsorption can introduce some impurity. Sorry, the product will be like this here. large and the HOMO-LUMO gap is small, (Bersuker, 1996) as for example in. 1 bromovutaneit will also go through s and 2. The ammonia solvated copper(II) ion has a Jahn-Teller distorted octahedral.

The productnext compound given to us is 2 bromo.

This will be the product next compound, given is 1 fluoro butanehere. Also it will go through the same as into mechanismand.

#Homo and lumo of ammonia plus

I plus n c next compound given to us is 2 bromobutaneto broma butane. O then i minus will attack here and c l minus will be reductedthe transition state will be this. Suppose it is reacting with n a i, then it will go through s n 2. The first compound given to us is 2 chloroblutanetwo chlorobutane. In the question we are asked to show s m 1 or s m 2 attack for the compounds.